give the correct answer dont try to give any wrong answer
ABCD is rectangle and P is a point such that PA =5, PC=4 and PD=3 find PB
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by Pythagoras theorem
pd²+ad²=pa²
3²+ad²=5²
ad=√(25-9
=4
as it's a rectangle
ad=bc
again applying the same theorem
pd²+bc²=pb²
3²+4²=pb²
pb=5(answer)
pd²+ad²=pa²
3²+ad²=5²
ad=√(25-9
=4
as it's a rectangle
ad=bc
again applying the same theorem
pd²+bc²=pb²
3²+4²=pb²
pb=5(answer)
Anubhavdeb:
wrong answer
can u plzz provide picture
the location of point p seems like a doubt
yes for me also
the question needs to be checked thoroughly
ans is 16sqrt2
this is the correct one
cm
no
answer is 4√2
Answered by
3
Hope this helps.........
Attachments:
you don't know how to square root
√32 = 4√2
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