Give the correct order of electronegativity of the following elements :
F Cl O Br
PLEASE EXPLAIN WITH QUALITY REASONS..!!
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Answers
Answer:
F>O>Cl>Br
fluorine is highly electronegative because it has 5 electron in it's 2p shell.
oxygen is situated at right part of the pereodic tables . as you move from left to right electronegative increases. and oxygen has 6 valence electron it can still attract 2more electron .
cl has more electronegative because it has got greater tedency to attract an electronic from another atom.
Br , the electron are further away from nucleus and better shielded from the neclear charge and thus not as attracted from the nucleus thats why electronegative is less in Br
Solution :-
First Thing to know - What is electronegativity ?
It is the property of any atom of a element to form a Covalent bond.
How to relate Electronegativity between two or more elements ?
Electronegativity of elements increases from the bottom of the periodic table to top.
Electronegativity of elements increases from left to right of the periodic table
Note :- We are not considering Nobel gasses as they have complete octate/duet .
So we are here with the elements :-
F :- Florine
Atomic No :- 9
Period :- 2
Group :- VII A or 17
Cl :- Chlorine
Atomic No :- 17
Period :- 3
Group :- VII A or 17
O :- Oxygen
Atomic No :- 8
Period :- 2
Group :- VI A or 16
Br :- Bromine
Atomic No :- 35
Period :- 4
Group :- VII A or 17
Now via group :-
In Group 2 :- O , F
In Group 3 :- Cl
In Group 4 :- Br
So we have got in electronegativity series :-
( O , F ) > Cl > Br
Now the comparison Between O and F
Period of O :- VI A or 16
Period of F :- VII A or 17
→ F > O