Question

Give the correct solution with full explanation.

(States of matter chapter, class 11)

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Answer 1

Solution:-

Given:-

:- One mole of monoatomic real gas Equation is

P(V - b ) = RT

Where b is constant and n = 1

The real gas equation is

$\implies \rm \: \sf \bigg(p + \dfrac{a {n}^{2} }{v {}^{2} } \bigg) \bigg(v - nb \bigg) = nRT$

As we know that

$\rm \: : \sf \: \dfrac{a {n}^{2} }{v^{2} } \: is \: attraction \: between \: the \: molecules$

Comparing when both equation we get attraction between the molecules is zero

Now when we look graph its given v(r) v/s r

When

$\to \: \sf \: r \downarrow \: where \: v(r) \: is \: constant \:$

$\sf \: \to \: r \downarrow \downarrow \: so \: replusive \: force \: domain \: \: \: \: so \: v(r) \: increase$

Now look at the graph

option :1 :- V(r) is decrease and the constant

so option 1 is incorrect

Option:2 :- so v(r ) is constant

so option 2 is incorrect

Option :4 :- At certain time is increase

so option 4 is incorrect

Now look at

option: 3 :- Now when r is decrease its v(r) constant and r is more decrease so v(r) is increased

So option c is correct