give the d.f of work done
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Very nice question! You can see this from the second Newton's law:
m
¨
x
=F(x)
Now I would like to integrate this equation of motion with respect to time, to arrive at the energy conservation. To do so I multiply both sides with
˙
x
:
m
¨
x
⋅
˙
x
=F(x)⋅
˙
x
and finally integrate:
m∫dt
¨
x
⋅
˙
x
=∫dtF(x)⋅
˙
x
The l.h.s. gives me the kinetic energy. The r.h.s. gives me exactly the integral in question:
1
2
m
˙
x
2=∫dx⋅F(x)
So the work done by the force is the kinetic energy of the particle (up to an integration constant representing its total energy).
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