Physics, asked by ASPIRANTT, 2 months ago

give the dimensional analysis of plank's constant​

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Answered by Anonymous
9

AnsWer :

Planks constant :-

\longrightarrow\sf E = h \nu

\longrightarrow\sf E = h  \times \dfrac{1}{T}

\longrightarrow\sf h = E  T

\longrightarrow\sf [h]= [E]  [T]

•Dimensions of Energy (E) = [M¹L²T-²]

•Dimensions of Time Period (T) = [M⁰L⁰T¹]

\longrightarrow\sf [h]= [M^{1} L^{2} T^{ - 2} ]  [M^{0} L^{0}T^{1} ]

\longrightarrow\bold{ [h]= [M^{1} L^{2} T^{ - 1} ] }

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