Question

Give the divisibility rule of 9 and 8 . If 31z5 is a multiple of 9, where z is a digit, what is the value of z
please tell it's urgent​

Answer 1

Answer:

Playing with Numbers

∵ 31z5 is divisible by 9. ∴ (9 + z) must be equal to 0, or 9 or 18 or 27, ... But z is a digit. ∴ 9 + z = 0 or 9 + z= 18 If 9 + z = 0, then z = 0 and if 9 + z = 18, then z = 9.

Answer 2

Step-by-step explanation:

DIVISIBILITY RULE OF 9= IF THE SUM OF ALL THE DIGITS OF A NUMBER IS DIVISIBLE BY 9 THEN THE WHOLE NUMBER IS DIVISIBLE BY 9

DIVISIBILITY RULE OF 8= IF THE LAST 3 DIGITS OF A NUMBER IS DIVISIBLE BY 8 THEN WHOLE NUMBER IS DIVISIBLE BY 8

31Z5 IS DIVISIBLE BY 9 THEN THE SUM OF ITS DIGIT SHOULD BE DIVISIBLE BY 9

ATQ

3+1+Z+5 IS DIVISIBLE BY 9

9+Z IS DIVISIBLE BY 9

SO Z=0

LOWEST VALUE OF Z=0

BUT YOU CAN ALSO WRITE THE VALUE AS 9

don't go ahead of 9 because it will become a 2 digit no.