.) Give the electronic configuration, bond order and magnetic property forO2
molecule
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Answer:
As it can be seen from the MOT of O
2
, The electrons in the highest occupied molecular orbital are unpaired therefore it is paramagnetic in nature. Also, the bond order can be calculated as [N
b
−N
a
]/2=[10−6]/2=2. Therefore there is a double bond present as O=O.
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