Give the equation of a line which
through the point (3,4)
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Only one line can pass through two points... Required equation is( 3- x ) =m(4-y) and it could be of any form like 3x+4y =0.... I am not able to understand what kind of equation you want!
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Answer:
1st quadrant
x=3
y=4
Step-by-step explanation:
Take the equation in slope-intercept form which is y=mx+c
If it passes through P(p,q) and m=a, then the value of c can be obtained by putting
x=p,y=q and m=a
Given slope of the equation =5 and passes through (3,4).
The general equation of line is : y=mx+c
Thus. line is y=5x+c
It passes through (3,4).
4=5(3)+c
c=4−15=−11
Thus, the line is y=5x−11.
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