give the equation of motion for position velocity relation
Answers
Answered by
1
Equation for position velocity relation..
Consider graph given in below image.
We know that distance travelled (s) by a body in time (t) is given by the area under the line AB which is area of trapezium OABC.
So we have,
Distance travelled = s = Area of Trapezium OABC
S = (sum of 2 parallel sides) x height/2=(OA+CB) x OC/2
Since, OA+CB = u+v and OC=t,
Then we gets=(u+v)t/2 -------------(1)
From, velocity time relation,
t=v-u/a
Substituting the value of 't' in equation (1)
We get, s = (u+v)/2(v-u)/2
or we have > v²=u²+2as
Which is equation for position velocity relation.
Consider graph given in below image.
We know that distance travelled (s) by a body in time (t) is given by the area under the line AB which is area of trapezium OABC.
So we have,
Distance travelled = s = Area of Trapezium OABC
S = (sum of 2 parallel sides) x height/2=(OA+CB) x OC/2
Since, OA+CB = u+v and OC=t,
Then we gets=(u+v)t/2 -------------(1)
From, velocity time relation,
t=v-u/a
Substituting the value of 't' in equation (1)
We get, s = (u+v)/2(v-u)/2
or we have > v²=u²+2as
Which is equation for position velocity relation.
Attachments:
Similar questions