Question

Give the equations of two lines passing through (2, 14). How many more such line
are there, and why?​

Answer 1

Answer:

x+y=16. 3x+y=20

Step-by-step explanation:

taking x=2,y=14

x+y=2+14=16

3x+y=3(2)+14=6+14=20

from one point there are infinite lines passing through it's in Euclid theorems

Answer 2

Solution:

We know that infinite number of lines passes through a point.

Equation of 2 lines passing through (2,14) should be in such a way that it satisfies the point.

Let the equation be, 7x = y

7x–y = 0

When x = 2 and y = 14

(7×2)-14 = 0

14–14 = 0

0 = 0

L.H.S = R.H.S

Let another equation be, 4x = y-6

4x-y+6 = 0

When x = 2 and y = 14

(4×2–14+6 = 0

8–14+6 = 0

0 = 0

L.H.S = R.H.S

Since both the equations satisfies the point (2,14), than say that the equations of two lines passing through (2, 14) are 7x = y and 4x = y-6.

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