Give the formula of summation ?
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Answered by
3
Hey there,
According to the formula of summation=
∑(1)=n
∑n=n(n+1)/2
∑n²=n(n+1)(2n+1)/6
∑n³=n²(n+1)²/4
∑k=kn
∑(n+k)=∑n+∑k
∑an=sn
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
According to the formula of summation=
∑(1)=n
∑n=n(n+1)/2
∑n²=n(n+1)(2n+1)/6
∑n³=n²(n+1)²/4
∑k=kn
∑(n+k)=∑n+∑k
∑an=sn
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
07161020:
thanks evildrackur
Answered by
3
Sum of 1st n positive integers = n(n+1)/2
Sum of squares of 1st n positive integers = n(n+1)(2n+1)/6
Sum of cubes of 1st n positive integers = n^2(n+1)^2/4.
Hope this helps!
Sum of squares of 1st n positive integers = n(n+1)(2n+1)/6
Sum of cubes of 1st n positive integers = n^2(n+1)^2/4.
Hope this helps!
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