give the geometry of following equation and also identify the line parallel to which axis 1. x+1=0 2.3y+4=10
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Answered by
1
Answer:
nahi ata but is wrong question
Answered by
6
First, let's find the value of
y
for
(
3
,
y
)
to be on the graph of the function.
y
=
3
(
3
)
2
−
5
(
3
)
+
2
y
=
27
−
15
+
2
y
=
14
Next, differentiate using the power rule. Let your function be
f
(
x
)
, then:
f
'
(
x
)
=
6
x
−
5
Now, plugging in our value of x to find the slope:
f
'
(
3
)
=
6
(
3
)
−
5
f
'
(
3
)
=
13
∴
The slope of the tangent is
13
. Now we know a point on the original function
(
3
,
14
)
and the slope of the tangent, 13.
We will use point slope form to determine the equation of the tangent.
y
−
y
1
=
m
(
x
−
x
1
)
y
−
14
=
13
(
x
−
3
)
y
−
14
=
13
x
−
39
y
=
13
x
−
25
∴
The equation of the tangent is
y
=
13
x
−
25
.
Hopefully this helps!
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