Question

give the hybridization of the central atom and expected geometry of the following molecules PF5,IF7​

Answer 1

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The hybridization of the central atom, P, is sp3d because it's shape is trigonal bipyramidal.

In the molecule IF 7 the the central atom I has 7 valence electrons out of which all 7 electrons form 7 sigma bonds implies thestearic number is 7 and therefore the hybridization is sp³d³ and the geometry is same as shape which is pentagonal bipyramidal. In which 5 F are in equatorial position and 2 F atoms are at axial position.

Answer 2

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The hybridization of the central atom, P, is sp3d because it's shape is trigonal bipyramidal.

The hybridization of the central atom, P, is sp3d because it's shape is trigonal bipyramidal.In the molecule IF 7 the the central atom I has 7 valence electrons out of which all 7 electrons form 7 sigma bonds implies thestearic number is 7 and therefore the hybridization is sp³d³ and the geometry is same as shape which is pentagonal bipyramidal. In which 5 F are in equatorial position and 2 F atoms are at axial position.