Question

Give the hybridization of the central atom in XeO3

Answer 1

Answer:

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Explanation:

Z = Number of Valence electrons on central atom + (number of monovalent groups attached) - (charge with sign)

Now, divide Z by 2.

If z/2 =2 sp

z/2=3 sp2

z/2=4 sp3

z/2=5 sp3d

z/2=6 sp3d2

Alright then! now lets use this to figure out the hybridization of XeO3

Central atom:- Xe

Number of Valence e = 8 (hope you didnt have to count that, after all Xe is a noble gas)

Monovalent groups attached = 0 (O is bivalent)

charge = 0

so z = 8

z/2 = 4

so Sp3

now, the only point of figuring out hybridizations IN MY OPINION is to figure out the geometry.

so the expected geometry should be tetrahedral, but there are only 3 bonded groups, and 1 lone pair.

So the geometry comes out to be trigonal pyramidal.