give the hybridization of the central atom of HeO3
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Answer:
Number of hybrid orbitals = number of σ bonds + number of lone pairs ⇒3 σ bonds +1 lone pair =4 ∴ Hybridisation of N is ...
Answered by
0
Answer:
Number of hybrid orbitals = number of σ bonds + number of lone pairs
⇒3σ bonds +1 lone pair =4
∴ Hybridisation of N is sp
3
and geometry of the molecule is pyramidal.
Explanation:
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