Chemistry, asked by VaibhavSawant7, 10 months ago

Give the Iupac names


Name the following.
K4[Ni(CN)4]
(NH4)3[Fe(SCN)6]
Na2[Ni(CN)4]
[Fe(ox)3]3-
[Co(NH3)5Cl]Br2
[Cr(OH2)4Cl2]Cl
[Pt(NH3)2]Cl2
Na2[MoOCl4]
[Cr(OH2)6](NO3)3
[Fe(NH3)6]SO4
(NH4)2[CoCl4]
Cr(NH3)4Cl2
[Co(P(CH3)3)4]2(SO4)3
[Ni(OH2)6]Cl2


Write formulas for the following.
potassium hexacyanoferrate(III)
sodium hexafluoroaluminate(III)
pentaaquabromomanganese(III) sulfate
hexaamminechromium(III) nitrate
sodium tetrahydroxochromate(III)
hexaammineruthenium(III) tetrachloronickelate(II)
tetraamminecopper(II) pentacyanohydroxoferrate(III)
potassium diaquatetrabromovanadate(III)



Provide the name or chemical formula for the following complex compounds or ions.
[Al(OH2)6]Br3
[Cr(NH3)6]Cl3
potassium hexafluoroferrate (III)
tetrahydroxozincate (II) ion
[Co(OH2)4Cl2]Cl
[Cu(NH3)4]+2
potassium hexachlorostannate (IV)
tetraamminedichloroplatinum (IV) hexachloroplatinate (IV)​

Answers

Answered by saivivek16
4

Explanation:

[Al(OH2)6]Br3=>>>Hexaaquaalumimum bromide.

[Cr(NH3)6]Cl3=>> potassium hexafluoroferrate (III)

tetrahydroxozincate (II) ion=>>[Cu(NH3)4]+2

potassium hexachlorostannate (IV)=>>K2(sncl6)

tetraamminedichloroplatinum (IV) (or)

hexachloroplatinate (IV)=>>(or(NH3)4cl2)(ptcl6)

Hope it will help you

✌️sai

Answered by Anonymous
3

Al(OH2)6]Br3=>>>Hexaaquaalumimum bromide.

[Cr(NH3)6]Cl3=>> potassium hexafluoroferrate (III)

tetrahydroxozincate (II) ion=>>[Cu(NH3)4]+2

potassium hexachlorostannate (IV)=>>K2(sncl6)

tetraamminedichloroplatinum (IV) (or)

hexachloroplatinate (IV)=>>(or(NH3)4cl2)(ptcl6)

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