Give the magnitude of the magnetic force on the electron for the three cases of its motion shown here
Answers
Answer:
electrons move through the direction of current
Explanation:
Step-by-step explanation:
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Answer:
Magnetic fields exert a force on a moving charge q, the magnitude of which is
F = qvB sin θ,
where,
θ is the angle between the directions of v and B.
The SI unit for magnetic field strength B is the tesla (T), which is related to other units by
1 T = 1 N/ C*m/s = 1 N/A*m
The direction of the force on a moving charge is given by right hand rule 1 (RHR-1): Point the thumb of the right hand in the direction of v, the fingers in the direction of B, and a perpendicular to the palm points in the direction of F.
The force is perpendicular to the plane formed by v and B. Since the force is zero if v is parallel to B, charged particles often follow magnetic field lines rather than cross them.