Question

give the mass no and atomic no of elements on the right hand side of the decay process
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Answer 1

Answer:

the complete equation giving mass number and atomic number of element are 220Ru^86______216Po84 +4He^2

for Polonium Z=84,A=216

for helium Z=2,A=4

Here Z is atomic number and A is atomic mass.( please like it) and follow