Give the mechanism of kolbe's electrolysis of ch3cook
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Ans: The electrolysis of salts of Carboxylic acids which finally produces alkanes is called Kolbe de-Carboxylation reaction. During this reaction Carbon dioxide is released at anode along with formation of alkanes. 2R-COONa (on Electrolysis) → R - R + 2CO2 + H2 + NaOHExample: Sodium acetate on electrolysis produces ethane. 2CH3COONa → CH3 - CH3+ 2CO2 + H2 + NaOH
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Answer:
Explanation:
AS IT IS ELECTROLYSIS THE REAGENT IS H2O
MECHANISM:
H2O=H+ + OH-
CH3COOK = CH3COO- + K+
TAKE REDUCTION OF CH3COO-
CH3COO.
TAKE HOMOLYTIC FISSION OF ABOVE FREE RADICAL
IT FORMS
METHYL FREE RADICAL
TAKE ANOTHER FREE RADICAL
IT FORMS ETHANE
SO PRODUCT
ETHANE + 2CO2+2KOH+H2
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