Question

give the mid point ofcollinear
question d(PR)=7,d(PQ)=10,d(QR)=3​

Answer 1

Answer:

We have, d(P, R) = 7; d(P, Q) = 10; d(Q, R) = 3

Now, d(P, R) + d(Q, R) = 7 + 3

Or, d(P, R) + d(R, Q) = 10

∴ d(P, Q) = d(P, R) + d(Q, R)

Hence, the points P, R and Q are collinear.

The point R is between P and Q i.e., P-R-Q.

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