give the molecular orbital configuration for NO molecule ... arrange the following in increasing order of stability NO+,. NO,. NO-..
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order of stability NO-<NO<NO+
1) The stability of ion is directly proportional to its bond order.
2) NO+ has 10 electrons (8 bonding, 2 antibonding)
Bond order = 3
NO has 11 electrons (8 bonding, 3 antibonding)
Bond order = 2.5
NO- has 12 electrons (8 bonding, 4 antibonding)
Bond order = 2
The number of bonding and antibonding electrons can be calculated by making the Molecular Orbital Theory diagram
3) So the increasing order of bond orders is NO-<NO<NO+
and hence the order of stability is also NO-<NO<NO+
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Answer:
AS BOND ORDER IS DIRECTLY PROPORTIONAL TO STABILITY
NO+ IS MORE STABLE
Explanation:
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