give the molecule orbital energy diagram of n2 and calculate the respect order write the mangnetic of n2
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Answered by
24
Answer:
Bond order=2(No. of electrons in bonding orbital)−(No. of electrons in anti−bonding orbital)
Bond order of N2=210−4=26=3⇒N≡N
Bond order of O2=210−6=24=2⇒O≡O
If orbitals contains unpaired electrons, it is paramagnetic. Otherwise diamagnetic.
N2 does not have unpaired electrons. So, it is diamagnetic.
O2 have 2 unpaired electrons. So, it is paramagnetic
Answered by
32
Answer:
Bond order=2(No. of electrons in bonding orbital)−(No. of electrons in anti−bonding orbital)
Bond order of N2=210−4=26=3⇒N≡N
Bond order of O2=210−6=24=2⇒O≡O
If orbitals contains unpaired electrons, it is paramagnetic. Otherwise diamagnetic.
N2 does not have unpaired electrons. So, it is diamagnetic.
O2 have 2 unpaired electrons. So, it is paramagnetic
Explanation:
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