Question

give the moment of inertia of a solid sphere about its diameter is 2/5MR^2,what is its moment of inertia about its tangent.​

Answer 1

(a) The moment of inertia (M.I.) of a sphere about its diameter = 2MR2/5

According to the theorem of parallel axes, the moment of inertia of a body about any axis is equal to the sum of the moment of inertia of the body about a parallel axis passing through its centre of mass and the product of its mass and the square of the distance between the two parallel axes.

The M.I. about a tangent of the sphere = 2MR2/5 + MR2 = 7MR2 / 5

Answer 2

The moment of inertia (M.I.) of a sphere about its diameter = 2MR2/5

According to the theorem of parallel axes, the moment of inertia of a body about any axis is equal to the sum of the moment of inertia of the body about a parallel axis passing through its centre of mass and the product of its mass and the square of the distance between the two parallel axes.

The M.I. about a tangent of the sphere = 2MR2/5 + MR2 = 7MR2 / 5