give the names of the elements and number of atoms of those elements present in the following compounds 1 sodium sulphate 2 quick lime 3 baking soda 4 ammonia 5 ammonium dichromate.
Answers
Answer:
Explanation:
The given compounds and their chemica formula are:
1. Sodium Sulphate - NaSO₄
2. Quick lime - CaO
3. Baking soda - NaHCO₃
4. Ammonia - NH₃
5. Ammonim dichromate - (NH₄)₂Cr₂O₇
In any chemical formula, the symbols represent name of element and number in subscript represent the number of atom of that particular element.
⇒In NaSO₄ = 1 sodium atom; 1 sulphur atom and 4 oxygen atoms are present.
⇒In CaO = 1 calcium atom and 1 oxygen atom are present.
⇒ In NaHCO₃ = 1 sodium atom; 1 hydrogen atom; 1 carbon atom and 3 oxygen atoms are present
⇒In NH₃ = 1 nitrogen atom and 3 hydrogen atoms are present.
⇒ In (NH₄)₂Cr₂O₇ = 2 Nitrogen atoms; 8 hydrogen atoms; 2 chromium atoms and 7 oxygen atoms are present.
The given compounds and their chemica formula are:
1. Sodium Sulphate - NaSO₄
2. Quick lime - CaO
3. Baking soda - NaHCO₃
4. Ammonia - NH₃
5. Ammonim dichromate - (NH₄)₂Cr₂O₇
In any chemical formula, the symbols represent name of element and number in subscript represent the number of atom of that particular element.
⇒In NaSO₄ = 1 sodium atom; 1 sulphur atom and 4 oxygen atoms are present.
⇒In CaO = 1 calcium atom and 1 oxygen atom are present.
⇒ In NaHCO₃ = 1 sodium atom; 1 hydrogen atom; 1 carbon atom and 3 oxygen atoms are present
⇒In NH₃ = 1 nitrogen atom and 3 hydrogen atoms are present.
⇒ In (NH₄)₂Cr₂O₇ = 2 Nitrogen atoms; 8 hydrogen atoms; 2 chromium atoms and 7 oxygen atoms are present.