Give the nature of roots of each equation
a.x2 +5x-6 = 0
B.y2
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0
Answer:
to find the nature of the roots, we have to find discriminant. D = b^2 - 4ac
a. D = (5)^2 - 4(-6)(1) = 25 + 24 = 49
hence real and distinct roots.
b. D = 0
hence real and equal roots
Answered by
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Answer:
X2+5x+6=0
(X2)2+(5x2)-(6)2
=x4+25x-36
B.y4
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