Math, asked by parekhsuchita8717, 1 year ago

Give the necessary and sufficient condition for a non-empty subset s of a ring (r, +, ) to be a subring of r.

Answers

Answered by Anonymous
0

Let (R,+,.) be a ring. A non empty subset S of R is called a subring of R if (S,+,.) is a ring.

For example the set {\displaystyle m\mathbb {Z} } {\displaystyle m\mathbb {Z} } which stands for {\displaystyle \{0,\pm m,\pm 2m\cdots \}} {\displaystyle \{0,\pm m,\pm 2m\cdots \}} is a subring of the ring of integers, the set of Gaussian integers {\displaystyle \mathbb {Z} [i]} {\displaystyle \mathbb {Z} [i]} is a subring of {\displaystyle \mathbb {C} } \mathbb {C} and the set {\displaystyle \mathbb {Z} _{4}} \mathbb {Z} _{4} has the set {\displaystyle \{{\overline {0}},{\overline {2}}\}} {\displaystyle \{{\overline {0}},{\overline {2}}\}} as a subring under addition and multiplication modulo 4.

I hope this will help you

If helpful then please select my answer as brainliest answer

And also follow me ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

Answered by lakshmilakku
0

Answer:

There's a subring theorem, which states that a non-empty subset S of a ring R =(r,+,*) is a subring of R with two necessary and sufficient conditions.

Step-by-step explanation

The above statement will be true if and only if the following conditions hold:

  1. S is closed under the  binary operation '+'
  2. If ∈ S then a^-1 ∈ S , where a^-1 denotes the inverse of a under the binary operation +.
  • A Subring of  R is a subset of a ring that is itself is a ring with binary operations of addition or multiplication.
Similar questions