Question

Give the output of the following

double x=8.7, y=4.5;

System.out.println(Math.min(Math.floor(x),y));​

Answer 1

$\textsf{\Large{\underline{\textbf{Snippet:}}}}$

$\texttt{double x=8.7, y=4.5;}$

$\texttt{System.out.println(Math.min(Math.floor(x),y));}$

$\textsf{\Large{\underline{\textbf{0utput:}}}}$

$\texttt{4.5}$

$\textsf{\Large{\underline{\textbf{About Functions in the Snippet:}}}}$

$\textsf{\large{{\textbf{Math.min():}}}}$

$\texttt{Returns the smaller of two double values.}$

$\texttt{That is, the result is the value closer to }$

$\texttt{negative infinity.}$

$\textsf{\large{{\textbf{Math.floor():}}}}$

$\texttt{Returns the largest (closest to positive infinity)}$

$\texttt{double value that is less than or equal to the}$

$\texttt{argument and is equal to a mathematical}$

$\texttt{integer.}$

Answer 2

Required Answer:-

Given Cσde:

$\tt double\ x=8.7,\ y=4.5;$

$\tt System.out.println(Math.min(Math.floor(x), y));$

To Find:

• Output (Java).

Output:

• 4.5

Explanation:

• Math.floor() function returns the lower integer for the given argument.
• So, Math.floor(x) = Math.floor(8.7) = 8.0
• Now, Math.min() function returns the minimum value of two numbers. Minimum of 8.0 and 4.5 is 4.5. Thus, the output is 4.5.

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