Question

Give the output of the following expressions. i) Math.sqrt(Math.floor(16.79)); ii) Math .max(Math.ceil(3.24),4);​

Answer 1

Answer:

i)4

ii)4

Explanation:

i)

Math.sqrt(Math.floor(16.79)); (since it is floor it will give you lower bound)

Math.sqrt(16);

=4

ii)Math.max(Math.ceil(3.24),4); (ceil will give you upper bound)

Math.max(4,4);

=4

Answer 2

Math.sqrt(Math.floor(16.79)) = 4  and Math .max(Math.ceil(3.24),4) = 4

i) Math.sqrt(Math.floor(16.79))

First solving function inside bracket

Math.floor(16.79)

floor function return the number to the lower greatest integers

hence Math.floor(16.79) = 16

Math.sqrt(16)

Sqrt function return the positive square root.

Math.sqrt(16) = 4

Hence Math.sqrt(Math.floor(16.79)) = 4

ii) Math .max(Math.ceil(3.24),4)

First solving function inside bracket

Math.ceil(3.24)

ceil function return the number to the higher lowest integer

hence Math.ceil(3.24) = 4

Math.max(4,4)

max function return the maximum of the given values

Here both values are same , hence will return 4

Math.max(4,4) = 4

Hence Math .max(Math.ceil(3.24),4) ​ = 4

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