Question

Give the possible expression for the length and breadth of the rectangle whose area is 6a2+a-12

Answer 1

6x^2 + x - 12
6x^2 + 9x - 8x - 12
3x × (2x+3) - 4 × (2x+3)
(3x-4) × (2x-3)

Answer 2

The possible expression for the length(l) of rectangle = (2a + 3) or, (3a - 4) and the possible expression for the breadth(l)  of rectangle = (2a + 3) or, (3a - 4) and

Step-by-step explanation:

Given,

The area of the rectangle = 6$a^2$ + a - 12

To find, the possible expression for the length(l) and breadth(b) of the rectangle = ?

We know that,

The area of the rectangle = Length(l) × Breadth(b)

⇒ Length(l) × Breadth(b) = 6$a^2$ + 9a - 8a - 12

⇒ Length(l) × Breadth(b) = 3a(2a + 3) - 4(2a + 3)

⇒ Length(l) × Breadth(b) = (2a + 3)(3a - 4)

∴ The possible expression for the length(l) of rectangle = (2a + 3) or, (3a - 4) and

The possible expression for the breadth(l)  of rectangle = (2a + 3) or, (3a - 4)