Give the preparation of alkyl halide by hcl and pcl5
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you have an alcohol group present.
CH3CH2CH2OH+PCl5→CH3CH2CH2Cl+POCl3+HCl
The general reaction looks like this:
ROH+HX→RX+H2O
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CH3CH2CH2OH+PCl5➡CH3CH2CH2Cl+POCl3+HCl
@Yuvi✔
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