Question

give the principle and procedur for the preparation of ch2cl2 in the laboratony​

Answer 1

Answer:

____ × (-10) = (-100) (iii) 9 × (-8) × (-2) = ______ (iv) 7 × (-12) × (-1) × (-1) = ______ (v) (-6) × (-13) × _____ = 78. (vi) (-5) × (-5) × _____ = 100.