Give the proof for the conservation of mechanical energy for a body falling freely under gravity
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If a body of mass m is in motion with speed v, then its kinetic energy is equal to K=12mv2. Let us now prove the conservation of the mechanical energy during a body falling freely. ... Hence, its kinetic energy will be K2=12mv2 and change in kinetic energy (ΔU) will be K2=12mv2.
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hope. it help u it is K2=12 mv 2
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