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Answer:
15 passengers have fare of Rs 30.
Explanation:
Let the number of passengers whose fare is Rs 30 be x and whose fare is Rs 100 be y.
According to the question,
x+y=40 ...(i)
30x+100y=2950 ...(ii)
Multiplying eq.(i) by 30, we get
30x+30y=1200 ...(iii)
30x+100y=2950 ...(iv)
Subtracting (iii) from (iv), we get
70y = 1750
=>y=1750/70
=>y=25
Putting y = 25, in eq.(i), we get
x = 15
So, number of passengers whose fare is Rs 30 = 15 passengers.
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