Question

give the reaction for the preparation of inorganic benzene.​

Answer 1

Chemical formula: B3H6N3

Melting point: −58 °C (−72 °F; 215 K)

Boiling point: 53 °C (127 °F; 326 K) (55 °C at 105 Pa)

Answer 2

Hey mate here is your answer:-

Borazine is an inorganic compound with the chemical formula B3H6N3. In this cyclic compound, the three BH units and three NH units alternate. The compound is isoelectronic and isostructural with benzene. For this reason borazine is sometimes referred to as “inorganic benzene”.

Chemical formula: B3H6N3

Melting point: −58 °C (−72 °F; 215 K)

Boiling point: 53 °C (127 °F; 326 K) (55 °C at 105 Pa).

Borazine is synthesized from diborane and ammonia in a 1:2 ratio at 250–300 °C with a conversion of 50%.

3 B2H6 + 6 NH3 → 2 B3H6N3 + 12 H2

An alternative more efficient route begins with lithium borohydride and ammonium chloride:

3 LiBH4 + 3 NH4Cl → B3H6N3 + 3 LiCl + 9 H2

In a two-step process to borazine, boron trichloride is first converted to trichloroborazine:

3 BCl3 + 3 NH4Cl → Cl3B3H3N3 + 9 HCl

The B-Cl bonds are subsequently converted to B-H bonds:

2 Cl3B3H3N3 + 6 NaBH4 → 2 B3H6N3 + 3 B2H6 + 6 NaCl.

Hope it helps:-