Question

Give the reduction of alkenes by sebatier senderen's method?

Answer 1

Hey there,

Reduction of alkenes and alkynes by Sebatier Senderen's method has following reaction-

RCH=CH2+H2--->RCH2CH3
CH2=CH2+H2--->CH3CH3
CH≡CH+2H2--->CH3CH3
CH3-C≡CH+2H2---->CH3CH2CH3

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Answer 2

reduction of alkenes