Question

give the right answer plz

$\red{don't spam}$​

Answer 1

$\sf \Large Solution!!$

Let ABCD be the parallelogram. AX is the altitude corresponding to the base CD. CY is the altitude corresponding to the base AD.

$\sf \large Given:$

$\sf \to AX=8\:cm$

$\sf \to CD=50\:cm$

$\sf \to CY=4\:cm$

$\sf \large To\:find:$

$\sf \to Base\:AD$

$\sf \large So,$

$\sf \to Area\:of\: parallelogram=Base(CD)\times Corresponding\: altitude(AX)$

$\sf \to Area=(50\times 8)\:cm^{2}$

$\sf \to Area=400\:cm^{2}\dots (i)$

$\sf \large Similarly,$

$\sf \to Area=Base(AD)\times Corresponding\: altitude (CY)$

$\sf \to Area=(AD\times 4)\:cm^{2}\dots (ii)$

$\sf \large Now,$

$\sf \to (AD\times 4)\:cm^{2}=400\:cm^{2}$

$\sf \to AD=\dfrac{400\:cm^{\cancel{2}}}{4\:\cancel{cm}}$

$\boxed{\blue{\sf AD=100\:cm}}$

Length of other pair of parallel side is 10 cm.

Thanks for asking!! :D