Math, asked by devanshhhhh18, 9 days ago

give the solution for the question​

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Answered by shreyasengupta1862
1

By\ chain\ rule,\\ d/dx (log(cos e^r ))\\\\= 1/cos(e^r )*d/dx (cose^r ) = 1/cos(e^r)1*(\−sine^r )*d/dn(e^r )\\\\= \−sin(e^r )/cos(e^r) *e^r =  -e^rtan(e^r)

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Answered by devg8020
0

Answer:

hurre

bhen

ke lawde

madhrchod

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