Question

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Answer 1

Answer:

40 %

Explanation:

vd O2 = 16

vd O 3 = 24

vd mix = 20

so let moles of O2 : O 3 = n : 1 ( or clearly n= 1 )

20 = ( 16 n + 24 ) / ( n + 1 )

n = 1

Therefore mass% = ( 16 n/ (16 n + 24 ) ) * (100%) = 40%

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