Question

give the solution of this question​

Answer 1

Answers

3AX = 2AC

Hence proved

Step-by-step explanation:

In the given parallelogram, ABCD

P is midpoint of side CD as shown in figure.

Join BP which intersect diagonal AC at x.

Please find attachment for figure.

In ΔABX and ΔCPX

∠ABX = ∠CPX   ( alternate angle of parallel line, CD||AB)

∠BAX = ∠PCX    ( alternate angle of parallel line, CD||AB)

Therefore, ΔABX ≈ ΔCPX  (By AA similarity property)

If two triangles are similar then their corresponding sides are in proportion.

Therefore,

\dfrac{AB}{PC}=\dfrac{AX}{CX}

But  AB = 2PC    (AB=CD opposite side of parallelogram and P is mid point of CD)

CX = AC - AX

Put the value in equation

\dfrac{2PC}{PC}=\dfrac{AX}{AC-AX}

2AC-2AX=AX

2AC=3AX

hence proved

Answer 2

Answer:

this is ax and ac not equal