give the solution to questions below:-
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1. Diagonal of a cube = √3 a
√10 = √3a
10 = 3a^2
a^2 = 10/3
a = side = √(10/3) cm
Volume of cube = (side)^3 = a^3
= (10/3) × √(10/3)
= (10√10)/(3√3) cm^3
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2. angle CAB = 100°
√10 = √3a
10 = 3a^2
a^2 = 10/3
a = side = √(10/3) cm
Volume of cube = (side)^3 = a^3
= (10/3) × √(10/3)
= (10√10)/(3√3) cm^3
-------------–-----------------------
2. angle CAB = 100°
rosy8:
give proper explanation of second answer or I will report your answer
okay
angle D & angle C are on same segment AB, and angle on same segment are equal. Therefore angle D equals angle C = 50° . Now in triangle ADB , B=30° & D=50°, hence angle A=100°
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