Give the squares of the first ten natural numbers
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The sum of the squares of the first ten natural numbers is, 12 + 22 + ... + 102 = 385 The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10)2 = 552 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640
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You can also solve this question by directly calculating the mean of the square of the first 10 natural numbers namely 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10. Their squares will be 1, 4, 9, 16, 25, 36, 49, 64, 81 and 100. Using the formula of mean, we get 1+4+9+16+25+36+49+64+81+10010=38510
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