Give the styx code of B4 H10 and which type of bond present in it?
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Hello dear,
● Answer-
STYX code = 4 0 1 2
● Explaination-
Given compound B4H10
Here, p = 4 and q = 10-4 = 6
We know the relationship,
p = s+t = 4 ...(1)
q = s+x = 6 ...(2)
p-q/2 = t+y = 4-3 = 1 ...(3)
Solving (1), (2) & (3),
s = 4
t = 0
y = 1
x = 2
STYX formula = 4 0 1 2
Molecule of B4H10 contains -
4 B-H-B bonds
0 B-B-B bond
1 B-B bond
2 BH2 groups.
Hope this is useful...
● Answer-
STYX code = 4 0 1 2
● Explaination-
Given compound B4H10
Here, p = 4 and q = 10-4 = 6
We know the relationship,
p = s+t = 4 ...(1)
q = s+x = 6 ...(2)
p-q/2 = t+y = 4-3 = 1 ...(3)
Solving (1), (2) & (3),
s = 4
t = 0
y = 1
x = 2
STYX formula = 4 0 1 2
Molecule of B4H10 contains -
4 B-H-B bonds
0 B-B-B bond
1 B-B bond
2 BH2 groups.
Hope this is useful...
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