Give the temperature on Fahrenheit scale which is numerically equal to and opposite of in Celsius scale.Show Full Procedure.
AcharyaVII:
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Answered by
1
°F = (9*°C/5) + 32
a/q,
°F = -°C
now,
°C = -9*°C/5 + 32
°C+9*°C/5 = 32
14*°C/5 = 32
°C = 32*5/14 = 80/7
Therefore °F = -80/7
a/q,
°F = -°C
now,
°C = -9*°C/5 + 32
°C+9*°C/5 = 32
14*°C/5 = 32
°C = 32*5/14 = 80/7
Therefore °F = -80/7
Answered by
0
°F = (°C * 9/5) + 32
°C = (°F - 32) * 5/9To find the temperature when both are equal, we use an old algebra trick and just set ºF = ºC and solve one of the equations.°C = (°C * 9/5) + 32
°C - (°C * 9/5) = 32
-4/5 * °C = 32
°C = -32 * 5/4
°C = -40°F = (°F * 9/5) + 32
°F - (°F * 9/5) = 32
-4/5 * °F = 32
°F = -32 * 5/4
°F = -40
°C = (°F - 32) * 5/9To find the temperature when both are equal, we use an old algebra trick and just set ºF = ºC and solve one of the equations.°C = (°C * 9/5) + 32
°C - (°C * 9/5) = 32
-4/5 * °C = 32
°C = -32 * 5/4
°C = -40°F = (°F * 9/5) + 32
°F - (°F * 9/5) = 32
-4/5 * °F = 32
°F = -32 * 5/4
°F = -40
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