Question

Give thetype of the hybridization of all the carbons in thefollowing compound. ch3-ch=ch-ch2-cooh

Answer 1

Answer:

Explanation:

CH3-CH=CH-CH2-COOH

1. 2. 3. 4. 5.

Let the above numbers be the numbers of each carbon.

So,

1. The carbon is sp3 hybridised, since it forms 4 sigma bonds with 3 C-H and one C-C bonds, that is 4 sp3 hybrid orbitals overlaps with the orbitals of H and carbon to form 4 sigma bonds.

2. The carbon is sp2 hybridised, it forms 3 sigma bonds using the 3 sp2 hybridised orbitals with the orbitals of H and C and one pi bond is formed with the un hybridised p orbital with the orbital of C.

3. The carbon is sp2 hybridised, it forms 3 sigma bonds using the 3 sp2 hybridised orbitals with the orbitals of H and C and one pi bond is formed with the un hybridised p orbital with the orbital of C.

4. The carbon is sp3 hybridised, since it forms 4 sigma bonds with 2 H and 2 C-C bonds, that is 4 sp3 hybrid orbitals overlaps with the orbitals of H and carbon to form 4 sigma bonds.

5. The carbon is sp2 hybridised, it forms 3 sigma bonds using the 3 sp2 hybridised orbitals with the orbitals of 2 O and C and one pi bond is formed with the un hybridised p orbital with the orbital of O.