Question

give this answer and I will give branliest answer

Answer 1

hope you understood. all the best

Answer 2

let θ be the angle of object from ground

given,

horizontal range =2×maximum height

u²sin20÷g=2×u²sin³θ÷2g

2sinθcosθ=sin²θ

tanθ=2

so, cosθ=1by√5

sinθ=2by√5

therefore horizontal range

=u²sin20÷g

2u²sinθcosθ÷g

=4u² by 5g