Math, asked by jayashrigavit076, 10 months ago

Give this answer as early as possible. Please.​

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Answers

Answered by dhanalakshmis2524
1

Answer:

Step-by-step explanation:

tanA /(sec²A)²    +  cosA /( cosec²A)²

= ( sinA /cosA)  x (cos²A)²   + cosA  x (sin²A)²

=  sinA  . cos³A     + cosA . sin³A

= sinA cosA ( cos²A  + sin²A)

= sinA cosA (1)

 = sinA cosA

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