Question

give three distinct test apart from using an indicator you would carry out with solution of hydrochloric acid to illustrate the typical properties of an acid.

Answer 1

Hydrochloric acid reacts with active metals to liberate a colourless and odourless gas which burns with a popping sound liberating hydrogen gas.

Mg + 2HCl (dil.) → MgCl2 + H2. 

(b) Dilute hydrochloric acid reacts with metallic carbonate and bicarbonate to liberate a colourless and odourless gas with brisk effervescence which turns lime water milky i.e. CO2.

Na2CO3 + 2HCl (dil.) → 2NaCl + H2O + CO2 

Confirmatory test :

Ca(OH)2 + CO2 → CaCO3 + H2O.

(c) Dilute hydrochloric acid reacts with metallic sulphite and bisulphate to liberate a colourless gas having smell of burning Sulphur which turns acidified potassium dichromate paper from orange to green and potassium permanganate solution from purple to colourless.

Answer 2

Answer:

Explanation:

Hydrochloric acid reacts with active metals to liberate a colourless and odourless gas which burns with a popping sound liberating hydrogen gas.

Mg + 2HCl (dil.) → MgCl2 + H2. 

(b) Dilute hydrochloric acid reacts with metallic carbonate and bicarbonate to liberate a colourless and odourless gas with brisk effervescence which turns lime water milky i.e. CO2.

Na2CO3 + 2HCl (dil.) → 2NaCl + H2O + CO2 

Confirmatory test :

Ca(OH)2 + CO2 → CaCO3 + H2O.

(c) Dilute hydrochloric acid reacts with metallic sulphite and bisulphate to liberate a colourless gas having smell of burning Sulphur which turns acidified potassium dichromate paper from orange to green and potassium permanganate solution from purple to colourless