Chemistry, asked by NarayanRaj, 1 year ago

give three distinct test apart from using an indicator you would carry out with solution of hydrochloric acid to illustrate the typical properties of an acid.

Answers

Answered by heemank
41
Hydrochloric acid reacts with active metals to liberate a colourless and odourless gas which burns with a popping sound liberating hydrogen gas.

Mg + 2HCl (dil.) → MgCl2 + H2. 

(b) Dilute hydrochloric acid reacts with metallic carbonate and bicarbonate to liberate a colourless and odourless gas with brisk effervescence which turns lime water milky i.e. CO2.

Na2CO3 + 2HCl (dil.) → 2NaCl + H2O + CO2 

Confirmatory test :

Ca(OH)2 + CO2 → CaCO3 + H2O.

(c) Dilute hydrochloric acid reacts with metallic sulphite and bisulphate to liberate a colourless gas having smell of burning Sulphur which turns acidified potassium dichromate paper from orange to green and potassium permanganate solution from purple to colourless.



Answered by Amazingboy1622
8

Answer:

Explanation:

Hydrochloric acid reacts with active metals to liberate a colourless and odourless gas which burns with a popping sound liberating hydrogen gas.

Mg + 2HCl (dil.) → MgCl2 + H2. 

(b) Dilute hydrochloric acid reacts with metallic carbonate and bicarbonate to liberate a colourless and odourless gas with brisk effervescence which turns lime water milky i.e. CO2.

Na2CO3 + 2HCl (dil.) → 2NaCl + H2O + CO2 

Confirmatory test :

Ca(OH)2 + CO2 → CaCO3 + H2O.

(c) Dilute hydrochloric acid reacts with metallic sulphite and bisulphate to liberate a colourless gas having smell of burning Sulphur which turns acidified potassium dichromate paper from orange to green and potassium permanganate solution from purple to colourless

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