Question

give to equation for q of 10​

Answer 1

Answer:

Step-by-step explanation:

PREVIEW

7:00

Q 1 (i, ii & iii), Ex 4.2- Quadratic Equations - Chapter 4 - Maths Class ...

YouTube · Mathematics Class X

Mar 14, 2015

Answer 2

$\large\red{\underline{\underline{\bf{\blue{Given}}}}}$

A two digit number is 3 more than 4 times the sum of its digits. If 18 is added to the number, the digits are reversed.

$\large\red{\underline{\underline{\bf{\blue{To Find}}}}}$

• Original Number

• Reversed Number

$\large\red{\underline{\underline{\bf{\blue{Solution}}}}}$

Let the digit at

➥ Ones Place = y

➥ Tens Place = x

Then,

Original number = 10x + y

✞ According to 1st condition :-

➠ (10x + y) = 3 + 4(x + y)

➠ 10x + y = 3 + 4x + 4y

➠ 10x - 4x + y - 4y =

➠ 6x - 3y = 3

➠ 3 ( 2x - y) = 3

➠ 2x - y = 3/3 = 1

➠ 2x - y = 1

➠ y = 2x - 1. ----(1)

✞ When digits interchanged,

Reversed number = 10y + x

✞ According to Question :-

➠ (10x + y) + 18 = 10y + x

➠ 10x - x + y - 10y = -18

➠ 9x - 9y = -18

➠ 9(x - y) = -18

➠ x - y = -18/9 = -2

➠ x - y = -2. ---(2)

Put the value of (1) in (2) , We get,

➠ x - (2x - 1) = -2

➠ x - 2x + 1 = -2

➠ -x = -2-1

➠ x = 3

Now,

Put this value of x in (1) , We get,

➠ y = 2x -1

➠ y = 2×3 - 1

➠ y = 6 - 1 = 5

Hence,

• Original Number = 10x + y = 35

• Reversed Number = 10y + x = 53

.......═════════ ❃ ═════════........