Question

Give two examples to show that the product of two irrational numbers may be a rational number

Answer 1

Answer:

Step-by-step explanation:

root(3) x root(12)

=root(36)

=6

root(18) x root(8)

=root(144)

=12

Hope for brainliest!!!

Answer 2

Answer:

(a) $\sqrt{2} *\sqrt{2} =2$

(b) $\sqrt{3} *\sqrt{12} =6$

Step-by-step explanation:

An irrational number a real number only, but it is a type of real number which cannot be represented as a simple fraction.

A rational number is a number that can be expressed as the quotient or fraction $p/q$ of two integers, denominator is not zero.

OR

Rational numbers are numbers that can be expressed in $p/q$ form, where $p,q$ are integers and $q\neq 0$.

The examples can be:

(a) We know that $\sqrt{2}$ is an irrational number.

But $\sqrt{2} *\sqrt{2} =2$, $2$ is a rational number.

Similarly,

(b) $\sqrt{3} , \sqrt{12}$ are individually irrational numbers, but multiplying them gives rational number.

$\sqrt{3} *\sqrt{12} =\sqrt{36} =6$

#SPJ2