give two pairs of value of x and y such that(x,y) is equidistant from points (-1,8) and (3,4).
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Answer:
(8,1) ,(6,2) ...
Step-by-step explanation:
condition for x and y is that (x,y) is equidistant from points (-1,8) and (3,4).
=> (x-(-1) )² + (y-8)² = (x-3 )² + (y-4)²
=> (x+1)² + (y-8)² = (x-3 )² + (y-4)²
=> x²+1²+2x + y²+8²-16y = x²+3²+6x + y²+4²-8y
=> 1+2x +64-16y = 9+6x +16-8y
=> 2x -16y+65 = 6x -8y+25
=> 6x-2x-8y+16y+25-65 = 0
=> 4x+8y-40 = 0
=> x+2y-10 = 0
=> x+2y = 10
ie, x = 10 - 2y
when y = 1,
=> x = 10 - 2(1) = 10-2 = 8 so, one solution is (8,1)
when y = 2,
=> x = 10 - 2(2) = 10-4 = 6 so, another solution is (6,2)
and so on,
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